å°çšç»é¢ã§ãã
ringo,ãããŒã«,choucho,ã¿ã³ããªã³ã®ãããã芪åããŸå£é·è²¡åžã§ãð
3段å
ãã±ãããšå察åŽã«ãå
ãã±ããããããŸãã®ã§ã«ãŒããã¬ã·ãŒãããã£ã·ãåçŽã§ããŸããïœâª
ã¹ããŒããªã®ã«ããŒããå
¥ã£ãŠããã®ã§ãã£ã·ãåçŽã§ãã
chouchoã¯æ¥çåŸæçž«ãã¢ãããªã±ããŠããŸãã
泚)éããã®ãããããç©ãå
¥ããããŸããšç Žæã®åå ã«ãªããŸãã
ãããã«ããã³ã®çå°ã¯ããªã±ãŒããªãããããã®ãããã®ãããã匷ãæŠããªã©ç Žæã®åå ãšãªãå ŽåããããŸãã
ç¹ã«ã¢ãããªã±éšåã¯ãšãŠãããªã±ãŒãã«ãªã£ãŠããŸãã
ãããŸã§ãçŽ äººã®ãã³ãã¡ã€ãåã§ããç¹ã«å
åŽã®å£éã«å·ãæ¥çå€ã®ã¯ã¿åºããªã©å€å°ããå ŽåããããŸãã
äœæå·¥çšã§èãçå°ã¯ã©ãããŠãã·ã¯ãªã©ãçããŸãã
å£éã¯å
ã
硬ããã®å·ãçŒããè²ã ã©ã®ãããã®ããããŸãã
éãŸãæ¹ã®æãããã«ã¯å人差ããããŸãã®ã§åæã«éããå
šãéãŸããªã以å€ã¯äžè¯åã§ã¯ããããŸããã
ãåºã®ååã®ããã«å®ç§ããæ±ãã®æ¹ã现ãããšãããæ°ã«ãªãæ¹ã¯è³Œå
¥ããæ§ããã ããã
ããŒã¯ã¬ãŒã .ããŒãªã¿ãŒã³
ãã£ã³ã»ã«äžå¯
ãããããé¡ãããŸã(o^ïŒ^o)
ãããã«ããã³ã®æ£èŠåã§ãã³ã©ãåã§ããããŸããã
å人ã®ãã³ãã¡ã€ãåã§ãã
â
18.5cmã¢ã³ãã£ãŒã¯ãŽãŒã«ãå£é䜿çš
ãŸã€ã²ãååºããã®å£é䜿çš
â
暪çŽ22cm 瞊çŽ12cmïŒå£éå«ãŸãïŒããçŽ3.5cm
ãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒ
#ãããã#ã·ãã¯ãªè²åã#å粧ããŒã#å欧#å欧é貚#ãããã«ããã³ããŸå£#ãããã«ããã³é·è²¡åž#ã¿ã³ããªã³#choucho#ringo#ãããŒã«
å°çšç»é¢ã§ãã
ringo,ãããŒã«,choucho,ã¿ã³ããªã³ã®ãããã芪åããŸå£é·è²¡åžã§ãð
3段å
ãã±ãããšå察åŽã«ãå
ãã±ããããããŸãã®ã§ã«ãŒããã¬ã·ãŒãããã£ã·ãåçŽã§ããŸããïœâª
ã¹ããŒããªã®ã«ããŒããå
¥ã£ãŠããã®ã§ãã£ã·ãåçŽã§ãã
chouchoã¯æ¥çåŸæçž«ãã¢ãããªã±ããŠããŸãã
泚)éããã®ãããããç©ãå
¥ããããŸããšç Žæã®åå ã«ãªããŸãã
ãããã«ããã³ã®çå°ã¯ããªã±ãŒããªãããããã®ãããã®ãããã匷ãæŠããªã©ç Žæã®åå ãšãªãå ŽåããããŸãã
ç¹ã«ã¢ãããªã±éšåã¯ãšãŠãããªã±ãŒãã«ãªã£ãŠããŸãã
ãããŸã§ãçŽ äººã®ãã³ãã¡ã€ãåã§ããç¹ã«å
åŽã®å£éã«å·ãæ¥çå€ã®ã¯ã¿åºããªã©å€å°ããå ŽåããããŸãã
äœæå·¥çšã§èãçå°ã¯ã©ãããŠãã·ã¯ãªã©ãçããŸãã
å£éã¯å
ã
硬ããã®å·ãçŒããè²ã ã©ã®ãããã®ããããŸãã
éãŸãæ¹ã®æãããã«ã¯å人差ããããŸãã®ã§åæã«éããå
šãéãŸããªã以å€ã¯äžè¯åã§ã¯ããããŸããã
ãåºã®ååã®ããã«å®ç§ããæ±ãã®æ¹ã现ãããšãããæ°ã«ãªãæ¹ã¯è³Œå
¥ããæ§ããã ããã
ããŒã¯ã¬ãŒã .ããŒãªã¿ãŒã³
ãã£ã³ã»ã«äžå¯
ãããããé¡ãããŸã(o^ïŒ^o)
ãããã«ããã³ã®æ£èŠåã§ãã³ã©ãåã§ããããŸããã
å人ã®ãã³ãã¡ã€ãåã§ãã
â
18.5cmã¢ã³ãã£ãŒã¯ãŽãŒã«ãå£é䜿çš
ãŸã€ã²ãååºããã®å£é䜿çš
â
暪çŽ22cm 瞊çŽ12cmïŒå£éå«ãŸãïŒããçŽ3.5cm
ãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒãŒ
#ãããã#ã·ãã¯ãªè²åã#å粧ããŒã#å欧#å欧é貚#ãããã«ããã³ããŸå£#ãããã«ããã³é·è²¡åž#ã¿ã³ããªã³#choucho#ringo#ãããŒã«
ãµã€ãº
ãšã³çŽ22cmã¿ãçŽ12cmïŒéå£å«ãŸãïŒããçŽ3.5cm
çºéãŸã§ã®ç®å®
3æ¥
é éæ¹æ³ã»éæ
å®åœ¢ïŒå€ïŒéµäŸ¿
350åïŒè¿œå éæïŒ100åïŒ
å šåœäžåŸ
å šåœäžåŸ
è³Œå ¥ã®éã®æ³šæç¹
ããŒã¯ã¬ãŒã ããŒãªã¿ãŒã³ã§ãé¡ãããŸãã
åºæ¬çã«ãã£ã³ã»ã«ã¯åãä»ããŠãããŸããã
çŽ äººäœåã®ãããçå°ããããŠãããã·ã¯ããããªã©çŽ°ããé£ããããããããŸããã
å£éã¯è³Œå
¥ããæããããºããã£ããã硬ããã®ãããããŸãã
å£éã¯ã®ãã§æ¥çããŠããçºãç©ãå
¥ããããã匷ãåŒã£åŒµããšå€ããå ŽåããããŸãã
ãç解é ããæ¹ã®ã¿ã賌å
¥ãé¡ãããŸãã
â
ã¹ããæ®åœ±ã®ããå®éã®è²åã質æãšç°ãªãå ŽåããããŸãã
â
çºéã¯ç°¡æå
è£
ã«ãªããŸãã
ã®ãã察å¿äžå¯
å®éã®éæãšèª€å·®ãããå Žåãè¿éã§ããŸããã®ã§ãäºæ¿é¡ããŸãã
â
ãæå®ããªããã°å®åœ¢å€éµäŸ¿ïŒä¿èšŒãªãïŒã®çºéãšãªããŸãã
ãã以å€ã®çºéãè€æ°è³Œå
¥ã®å Žåã¯é£çµ¡ãã ããã
ãããããé¡ãããŸãâ¡